JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Analyzing +4 | -1

The number of solutions of

\sin 3 x=\cos 2 x

, in the interval

\left(\frac{\pi}{2}, \pi\right)

View answer and explanation

Correct option: D

Option D (1) is correct because after simplifying the equation

\sin 3x = \cos 2x

and considering the interval

(\frac{\pi}{2}, \pi)

, there is only one solution.

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