JEE MATHEMATICS MCQ: SET THEORY

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A=\left\{(x, y): x^2+y^2 \leq 1, x, y \in R\right\}

and

B=\left\{(x, y): x^2+y^2 \leq 4 ; x, y \in R\right\}

, then

View answer and explanation

Correct option: C

A-B=\phi

Option C (

A-B=\phi

) is correct because A is a subset of B, meaning all elements of A are also in B, so removing B from A results in an empty set.

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2 a_1 a_2 a_3 \ldots . . a_{2006}

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S

a N=\{a n: n \in N: b N=\{n b: n \in N\}

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F(n)

n

[\mathrm{F}(20) \cap \mathrm{F}(16)] \subseteq \mathrm{F}(\mathrm{y})

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A, 20 \%

10 \%

C

A

C

4 \%

A

C

2 \%

A