JEE MATHEMATICS MCQ: LIMITS

1 Easy

1 of 1

Analyzing +4 | -1

Let a be an integer such that

\lim\limits_{x \to 7} \frac{{18 - [1 - x]}}{{[x - 3a]}}

exists, where

[t]

is greatest integer

\leqslant t.

Then a is equal to:

View answer and explanation

Correct option: A

-6

Option A (-6) is correct because for the limit to exist, the left-hand limit (LHL) must equal the right-hand limit (RHL), which leads to a = -6.

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