JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

1+\sin \theta+\sin ^2 \theta+\ldots \ldots \infty=4+2 \sqrt{3}, 0 < \theta < \pi, \theta \neq \frac{\pi}{2}

, then

View answer and explanation

Correct option: D

\theta=\frac{\pi}{3}

\frac{2 \pi}{3}

Option D (

\theta=\frac{\pi}{3}

\frac{2 \pi}{3}

) is correct because these are the solutions to the equation derived from the infinite geometric series, within the given interval.

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\mathrm{X}

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0 < x < \pi

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