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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫−π/3−π/6dx1+tan⁡4x=\int\limits_{{-\pi / 3}}^{-\pi /6} \frac{d x}{1+\tan ^4 x}=
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Correct option: C
π12\frac{\pi}{12}
Option C (π12\frac{\pi}{12}) is correct because after applying the property of definite integrals and simplifying, the integral evaluates to π12\frac{\pi}{12}.

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