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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
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Application +4 | -1
Let f:[−1,0]→Rf:[-1,0] \rightarrow R be a function differentiable within the domain and that ∫−10(f(x))2dx=10\int\limits_{{-1}}^0(f(x))^2 d x=10 and f(−1)=2f(-1)=2. The value of the integral ∫−10xf′(x)f(x)dx\int\limits_{{-1}}^0 x f^{\prime}(x) f(x) d x, is:
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Correct option: C
−3-3
Option C is correct because integrating by parts and using the given information leads to the value -3.

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