JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

0 < \beta < \alpha < \frac{\pi}{4}, \cos (\alpha+\beta)=\frac{3}{5}

and

\cos (\alpha-\beta)=\frac{4}{5}

, then

\sin 2 \alpha

is equal to

View answer and explanation

Correct option: B

Option B (1) is correct because using the formula

\sin 2\alpha = \sin(((\alpha + \beta) + (\alpha - \beta)))

and the given values, we get

\sin 2\alpha = 1

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