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JEE PHYSICS MCQ: ELECTRIC POTENTIAL AND CAPACITANCE

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Application +4 | -1
An electric dipole of length 2 cm2 \mathrm{~cm} is placed with its axis making an angle of 30∘30^{\circ} to a uniform electric field 105 N/C10^5 \mathrm{~N} / \mathrm{C}. If it experiences a torque of 103Nm10 \sqrt{3} \mathrm{Nm}, then potential energy of dipole -
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Correct option: C
−30 J-30 \mathrm{~J}
Option C (-30 J) is correct because it calculates the potential energy of the dipole using the formula U=−pEcos⁡θU = -pE \cos \theta after finding the dipole moment pp from the torque equation.

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