JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

1 Easy

1 of 1

Application +4 | -1

\tan \,\,\alpha = \frac{b}{a},\,\;a > b > 0

and if

0 < \alpha < \frac{\pi }{4}

, then

\sqrt {\frac{{a + b}}{{a - b}}} \,\, - \,\,\sqrt {\frac{{a - b}}{{a + b}}}

is equal to

View answer and explanation

Correct option: A

\frac{{2\,\,\sin \,\,\alpha }}{{\sqrt {\cos \,\,2\alpha } }}

The correct answer is A (

\frac{{2\sin \alpha }}{{\sqrt {\cos \\,2\alpha } }}

) because simplifying the given expression using trigonometric identities leads to this result.

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