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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫−ππ2x(1+sin⁡x)1+cos⁡2xdx=\int\limits_{{-\pi}}^\pi \frac{2 x(1+\sin x)}{1+\cos ^2 x} d x=
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Correct option: B
π2\pi^2
Option B (π2\pi^2) is correct because after simplifying the integral using properties of even and odd functions, the final result is π2\pi^2.

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