NEET UG CHEMISTRY MCQ: STATES OF MATTER

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298 \mathrm{~K}

, vapour pressure of methyl alcohol

\left(\mathrm{CH}_3 \mathrm{OH}\right)

is 96.0 torr. The mole fraction of

\mathrm{CH}_3 \mathrm{OH}

in a solution in which the partial vapour pressure of

\left(\mathrm{CH}_3 \mathrm{OH}\right)

is 24.0 torr at

298 \mathrm{~K}

View answer and explanation

Correct option: A

0.25

Option A (

0.25

) is correct because it is calculated using Raoult's Law, where the partial pressure of a component is equal to its mole fraction multiplied by its vapor pressure in the pure state.

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If for the gases, the critical temperatures are mentioned below i.e.

\begin{array}{cccccccccccccccccccc} {\underline {{\text{Gas}}} }&{\underline {\,{\text{Critical}}\,\,{\text{temperature}}} } \\ {\text{A}}&{{T_{{C_1}}}} \\ {\text{B}}&{{T_{{C_2}}}} \\ {\text{C}}&{{T_{{C_3}}}} \\ {\text{D}}&{{T_{{C_4}}}} \end{array}

{T_{{C_1}}} > {T_{{C_2}}} > {T_{{C_3}}} > {T_{{C_4}}}

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