What is the number of moles of Fe${\left( {{\rm{OH}}} \right)_3}\left( {\rm{s}} \right)$ that can be produced by allowing 1 mole of ${\rm{F}}{{\rm{e}}_2}{{\rm{S}}_3}$, 2 moles of ${{\rm{H}}_2}{\rm{O}}$ and 3 moles of ${{\rm{O}}_2}$ to react as $2{\rm{F}}{{\rm{e}}_2}{{\rm{S}}_3} + 6{{\rm{H}}_2}{\rm{O}} + 3{\rm{O}} \to 4{\rm{Fe}}{\left( {{\rm{OH}}} \right)_3} + 6{\rm{S}}?$

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Medium

1 of 1

Application +4 | -1

What is the number of moles of Fe

{\left( {\mathrm{OH}} \right)_3}\left( \mathrm{s} \right)

that can be produced by allowing 1 mole of

\mathrm{F}{\mathrm{e}_2}{\mathrm{S}_3}

, 2 moles of

{\mathrm{H}_2}\mathrm{O}

and 3 moles of

{\mathrm{O}_2}

to react as

2\mathrm{F}{\mathrm{e}_2}{\mathrm{S}_3} + 6{\mathrm{H}_2}\mathrm{O} + 3\mathrm{O} \to 4\mathrm{Fe}{\left( {\mathrm{OH}} \right)_3} + 6\mathrm{S}?

View answer and explanation

Correct option: C

1.34 mol

Option C (1.34 mol) is correct because the limiting reagent is H2O, and the stoichiometry of the reaction dictates the amount of Fe(OH)3 produced.