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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If 1b−c,  1c−a,  1a−b\frac{1}{{b - c}},\;\frac{1}{{c - a}},\;\frac{1}{{a - b}} be consecutive terms of an AP, then (b−c)2,  (c−a)2,  (a−b)2{\left( {b - c} \right)^2},\;{\left( {c - a} \right)^2},\;{\left( {a - b} \right)^2} will be in
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Correct option: B
AP
Option B (AP) is correct because if 1b−c,1c−a,1a−b\frac{1}{{b - c}}, \frac{1}{{c - a}}, \frac{1}{{a - b}} are in A.P., then (b−c)2,(c−a)2,(a−b)2{\left( {b - c} \right)^2},{\left( {c - a} \right)^2},{\left( {a - b} \right)^2} are also in A.P.

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