The mass defect in particular nuclear reaction if ${\rm{0}}{\rm{.3}}\,\,{\rm{g}}$. The amount of energy liberated in kilowatt hour is (Velocity of light $ = 3\,\, \times \,\,{10^8}\,\,{\rm{m}}{{\rm{s}}^{ - 1}}$

NEET UG PHYSICS MCQ: NUCLEI

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The mass defect in particular nuclear reaction if

\mathrm{0}\mathrm{.3}\,\,\mathrm{g}

. The amount of energy liberated in kilowatt hour is (Velocity of light

= 3\,\, \times \,\,{10^8}\,\,\mathrm{m}{\mathrm{s}^{ - 1}}

View answer and explanation

Correct option: D

7.5\,\, \times \,\,{10^6}

Option D (

7.5\, \times \,{10^6}

) is correct because the energy liberated is calculated using

E=mc^2

and then converted to kilowatt-hours.

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\mathrm{216}

\mathrm{125}

{ }_{92} X^{236} \rightarrow{ }_{56} Y^{141}+{ }_{36} Z^{92}+3 R

({R})

{R_0}\; = \mathrm{ }1.3fm

\left({ }_0^1 \mathrm{n}\right)

\left({ }_{92}^{235} \mathrm{U}\right)

1\,\,a.m.u = 931\,\,MeV