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JEE CHEMISTRY MCQ: ALDEHYDES & KETONES & CARBOXYLIC ACIDS

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The product formed in the following ozonalysis is CH2BrCH=CHCH3→O3C{H_2}BrCH = CHC{H_3}\xrightarrow{{{O_3}}}
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Correct option: B
CH3CHOC{H_3}CHO
The correct answer is B (CH3CHOC{H_3}CHO) because the ozonolysis of CH2BrCH=CHCH3C{H_2}BrCH = CHC{H_3} yields acetaldehyde.

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