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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Hard
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Application +4 | -1
The value of ∫e−1e2∣log⁡exx∣dx\int\limits_ {e^{-1}}^{e^2}\left|\frac{\log _e x}{x}\right| d x is
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Correct option: B
52\frac{5}{2}
Option B (52\frac{5}{2}) is correct because by splitting the integral based on the sign of log⁡ex\log_e x and using substitution, the integral evaluates to 52\frac{5}{2}.

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