JEE MATHEMATICS MCQ: ELLIPSE

1 Easy

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Application +4 | -1

If the area of the auxiliary circle of the ellipse

\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1(a > b)

is twice the area of the ellipse, then the eccentricity of the ellipse is

View answer and explanation

Correct option: B

\frac{{\sqrt 3 }}{2}

Option B (

\frac{{\sqrt 3 }}{2}

) is correct because it is the calculated eccentricity of the ellipse given the area condition.

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