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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The value of the sum ∑r=1n∑s=1nSrs  2r3s,whereSrs=0,  if  r≠s  andSrs=1,    if  r=s,\sum \limits_{r = 1}^n \sum \limits_{s = 1}^n {S_{rs}}\;{2^r}{3^s},\mathrm{where}{S_{rs}} = 0,\;\mathrm{if}\;r \ne s\;\mathrm{and}{S_{rs}} = 1,\;\;\mathrm{if}\;r = s, is
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Correct option: B
65(6n−1)\frac{6}{5}\left( {{6^n} - 1} \right)
Option B is correct because the sum simplifies to a geometric progression with a common ratio of 6, allowing for direct calculation using the geometric series formula.

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