JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

{p_1},{p_2},{p_3}

are respectively the perpendiculars from the vertices of a triangle to the opposite sides, then

\frac{{\cos \,\,A}}{{{p_1}}}\,\, + \,\,\frac{{\cos \,\,B}}{{{p_2}}}\,\, + \,\,\frac{{\cos \,\,C}}{{{p_3}}}

  is equal to

View answer and explanation

Correct option: B

\frac{1}{R}

Option B (

\frac{1}{R}

) is correct because the expression

\frac{{\cos A}}{{{p_1}}} + \frac{{\cos B}}{{{p_2}}} + \frac{{\cos C}}{{{p_3}}}

simplifies to

\frac{1}{R}

using trigonometric identities and the area of the triangle.

More Questions from PROPERTIES OF TRIANGLES

Practice All Chapter MCQs →

{p_1},{p_2},{p_3}

\Delta \;ABC

A,B,C

\Delta

p_1^{ - 2} + p_2^{ - 2} + p_3^{ - 2}

5k,\;6k,\;5k

k

\Delta \,ABC

a = \left( {b - c} \right)\sec \theta

\frac{{2\,\sqrt {bc} }}{{b - c}}\,\,\sin \,\,\frac{A}{2} =

\Delta \;ABC,\frac{{b + c}}{a}

\Delta = {a^2} - {\left( {b - c} \right)^2}

\Delta

\Delta \;ABC

\tan A

A

2 s