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NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
If ε0\varepsilon_0 is the permittivity of free space and EE is the electric field, then ε0E2\varepsilon_0 E^2 has the dimensions:
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Correct option: B
[ML−1T−2]\left[{M} {L}^{-1}{T}^{-2}\right]
Option B ([ML−1T−2]\left[{M} {L}^{-1}{T}^{-2}\right]) is correct because ϵ0E2\epsilon_0 E^2 represents energy density, which has dimensions of pressure (Force/Area).

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