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JEE CHEMISTRY MCQ: HYDROCARBONS

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Analyzing +4 | -1

S-I: Addition of

\mathrm{HBr}

to

\mathrm{HC} \equiv \mathrm{CCH}_2 \mathrm{CH}=\mathrm{CH}_2

give

\mathrm{HC}=\mathrm{CCH}_2 \mathrm{CHBr}-\mathrm{CH}_3

and not

\mathrm{H}_2 \mathrm{C}=\mathrm{CBrCH}_2 \mathrm{CH}=\mathrm{CH}_2

S-II: A triple bond is less reactive than a double bond towards electrophilic addition reaction.

View answer and explanation

Correct option: A

S-I

\&

S-II are true

Option A (S-I & S-II are true) is correct because both statements accurately describe the reactivity and product formation in the given reaction.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

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