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JEE PHYSICS MCQ: OSCILLATIONS

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Analyzing +4 | -1
The equation y=Asin⁡2(kx−ωt)y=A \sin ^2(k x-\omega t) represents a wave with:
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Correct option: B
Amplitude A/2{A} / 2, frequency ωπ\frac{\omega}{\pi}
Option B is correct because using the trigonometric identity sin⁡2(x)=12[1−cos⁡(2x)]\sin^2(x) = \frac{1}{2}[1 - \cos(2x)], the frequency becomes ωπ\frac{\omega}{\pi} and the amplitude becomes A2\frac{A}{2}.

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