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JEE MATHEMATICS MCQ: MULTIPLE AND SUBMULTIPLE ANGLES

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If cos⁡θa=sin⁡θb\frac{\cos \theta}{a}=\frac{\sin \theta}{b}, then asec⁡2θ+bcosec⁡2θ\frac{a}{\sec 2 \theta}+\frac{b}{\operatorname{cosec} 2 \theta} is equal to
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Correct option: A
aa
Option A (aa) is correct because the expression simplifies to acos⁡2θ+bsin⁡2θ=aa \cos 2\theta + b \sin 2\theta = a.

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