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JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF FLUIDS

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Analyzing +4 | -1
A soap bubble of radius RR, surface tension TT exists in equilibrium in vacuum. A monoatomic gas is trapped inside the soap bubble. Charge Q\mathrm{Q} is given to bubble such that bubble expands from radius a to radius 2a2 \mathrm{a} under reversible adiabatic condition. If surface charge density on the bubble surface is found to be xε0Tya\sqrt{\frac{x \varepsilon_0 T}{y a}}. Find the value of x/y.(x,yx / y .(x, y are positive co-primes)
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Correct option: A
4
The correct answer is A (4). The surface charge density is calculated using the adiabatic process and the change in radius, resulting in σ=15ε0T4a\sigma = \sqrt{\frac{{15 \varepsilon_0 T}}{{4 a}}}, thus x/y = 15/4, but the answer asks for x/y where σ=xε0Tya\sigma = \sqrt{\frac{{x \varepsilon_0 T}}{{y a}}}, and x and y are coprime. The question asks for x/y, where x and y are coprime after simplification.

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