Question

The position of a particle at time t is given by the relation $x\left( t \right) = \left( {\frac{{{v_0}}}{\alpha }} \right)\left( {1 - {c^{ - \alpha t}}} \right)$, where ${v_0}$ is a constant and $\alpha > 0$. The diemensions of ${v_0}$ and $\alpha $ are respectively

Accepted Answer

${M^0}{L^1}{T^{ - 1}}\,{	ext{and}}\,{T^{ - 1}}$

Answer

${M^0}{L^1}{T^0}\,{	ext{and}}\,{T^{ - 1}}$

Answer

${M^0}{L^1}{T^{ - 1}}\,{	ext{and}}\,L{T^{ - 2}}$

Answer

${M^0}{L^1}{T^{ - 1}}\,{	ext{and}}\,T$

NEET UG PHYSICS MCQ: UNITS & MEASUREMENTS

More Questions from UNITS & MEASUREMENTS