If $f\left( 1 \right) = 1,\;f'\left( 1 \right) = 2$, then $\mathop {\lim }\limits_{x \to 1} \frac{{\sqrt {f\left( x \right)} - 1}}{{\sqrt x - 1}}$ is

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

f\left( 1 \right) = 1,\;f'\left( 1 \right) = 2

, then

\lim\limits_{x \to 1} \frac{{\sqrt {f\left( x \right)} - 1}}{{\sqrt x - 1}}

View answer and explanation

Correct option: A

Option A (2) is correct because it is obtained by applying L'Hopital's rule to the limit and using the given values of f(1) and f'(1).

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