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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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The threshold frequency v0v_0 for a metal is 7.0×1014 s−17.0 \times 10^{14} \mathrm{~s}^{-1}. Calculate the kinetic energy of an electron emitted when radiation of frequency v=1.0×1015 s−1v=1.0 \times 10^{15} \mathrm{~s}^{-1} hits the metal.
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Correct option: A
1.988×10−19 J1.988 \times 10^{-19} \mathrm{~J}
Option A (1.988×10−19 J1.988 \times 10^{-19} \mathrm{~J}) is correct because it is the kinetic energy of the emitted electron calculated using Einstein's photoelectric equation.

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