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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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When lithium metal is irradiated with light of different wavelengths leads to stopping potential of 1.83 V1.83 \mathrm{~V} for λ=3000 A0\lambda=3000 \mathrm{~A}^0 and 0.80 V0.80 \mathrm{~V} for λ=4000 A0\lambda=4000 \mathrm{~A}^0 with the known charge on the electron, what is the work function of lithium?
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Correct option: A
2.3 eV2.3 \mathrm{~eV}
Option A (2.3 eV2.3 \mathrm{~eV}) is correct because it is calculated by using the photoelectric equation E=ϕ+eVsE = \phi + eV_s, where E is the energy of the photon, ϕ\phi is the work function, and VsV_s is the stopping potential.

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