Solid ${NaHCO}_3$ will be neutralized by $40.0 \mathrm{~mL}$ of $0.1\, {MH}_2 {SO}_4$ solution. What would be the weight of solid ${NaHCO}_3$ in gram?

JEE CHEMISTRY MCQ: SOME BASIC CONCEPTS OF CHEMISTRY

1 Medium

1 of 1

Application +4 | -1

Solid

{NaHCO}_3

will be neutralized by

40.0 \mathrm{~mL}

0.1\, {MH}_2 {SO}_4

solution. What would be the weight of solid

{NaHCO}_3

in gram?

View answer and explanation

Correct option: A

0.672 {gm}

Option A (0.672 gm) is correct because the weight of solid NaHCO₃ is calculated based on the stoichiometry of the reaction with H₂SO₄.

Practice All Chapter MCQs →

{H_2}O.

mol\,\,k{g^{ - 1}})

2.24 {~L}

{CH}_4

{CO}_2

0.5 \mathrm{M} \mathrm{H}_2 \mathrm{SO}_4

0.5 \mathrm{~g}

\mathrm{Cu}(\mathrm{II})