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JEE PHYSICS MCQ: WAVES

1 Medium
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Application +4 | -1
Equation of motion of wave in the same direction is given by y1=Asin⁡(ωt−Kx),y2=Asin⁡(ωt−kx+ϕ){y}_1={A} \sin (\omega {t}-{Kx}), {y}_2={A} \sin (\omega {t}-{kx}+\phi). The resultant amplitude of the medium particle will be
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Correct option: B
2Acos⁡ϕ22 A \cos \frac{\phi}{2}
Option B (2Acos⁡ϕ22 A \cos \frac{\phi}{2}) is correct because it represents the resultant amplitude of two waves interfering with a phase difference of ϕ\phi.

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