JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

\tan \alpha=1 / 7

and

\sin \beta=1 / \sqrt{10}

where

0 < \alpha, \beta < \pi / 2

, then

2 \beta

is equal to

View answer and explanation

Correct option: A

\pi / 4-\alpha

Option A (

\pi / 4 - \alpha

) is correct because it represents the value of

2\beta

given the conditions

\tan \alpha = 1/7

and

\sin \beta = 1/\sqrt{{10}}

, derived using trigonometric identities.

More Questions from TRIGONOMETRY RATIOS

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\tan \alpha=\frac{p}{q}

\alpha=6 \beta

\alpha

\frac{1}{2}[p \operatorname{cosec} 2 \beta-q \sec 2 \beta]

\cos 12^{\circ}+\cos 84^{\circ}+\cos 156^{\circ}+\cos 132^{\circ}

\triangle A B C

C

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\sin ^2 \frac{A}{2}+\sin ^2 \frac{B}{2}+\sin ^2 \frac{C}{2}=

\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=