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NEET UG BIOLOGY MCQ: EVOLUTION

1 Hard
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Application +4 | -1
If a population in Hardy-Weinberg equilibrium has 16%16 \% homozygous individuals with a recessive allele ' aa ' then the frequencies for given genotypes would be
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Correct option: A
AA %(36)\%(36) - Aa %(48)\%(48)
Option A (AA %(36)\%(36) - Aa %(48)\%(48)) is correct because it is calculated using the Hardy-Weinberg equation, where q2 is 0.16, q is 0.4, p is 0.6, p2 is 0.36, and 2pq is 0.48.

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