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NEET UG PHYSICS MCQ: DUAL NATURE OF RADIATION AND MATTER

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Analyzing +4 | -1

The de-Broglie wavelength of an electron,

\alpha

- particle and proton all having the same kinetic energy is respectively given as

{\lambda _e},\;{\lambda _\alpha }\;\;\mathrm{and\;}{\lambda _p}.

Then which of the following is not true?

View answer and explanation

Correct option: A

{\lambda _e} < {\lambda _p}

Option A (

\frac{{{E_e}}}{{{E_p}}} = \frac{v}{{2c}}

) is correct because it relates the kinetic energies of the electron and photon based on their de-Broglie wavelengths and velocities.

More Questions from DUAL NATURE OF RADIATION AND MATTER

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If the Broglie wavelengths associated with a proton and an

\alpha

- particle are equal, then the ratio of velocities of the proton and the

\alpha

- particle will be: If the wavelength of incident light changes from 400 nm to 300 nm, the stopping potential for photoelectrons emitted from a surface becomes approximately In photo-electric effect, when graph is plotted for stopping potential versus frequency of incident light, for different metals, then: The radiation corresponding to

3 \to 2

transition of hydrogen atom falls on a metal surface to produce photoelectrons. These electrons are made to enter a magnetic field of

3 \times {10^{ - 4}}\,T.

If the radius of the largest circular path followed by these electrons is 10.0 mm, the work function of the metal is close to The shortest wavelength of

X

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X

-ray tube depends on the Planck’s constant has the dimensions of