Phosphorus pentachloride dissociates as follows, in a closed reaction vessel,,br> ${\rm{PC}}{{\rm{l}}_5}\left( {\rm{g}} \right)\leftrightharpoons{\rm{PC}}{{\rm{l}}_3}\left( {\rm{g}} \right) + {\rm{C}}{{\rm{l}}_2}\left( {\rm{g}} \right)$ If total pressure at equilibrium of the reaction mixture is $p$ and degree of dissociation of ${\rm{PC}}{{\rm{l}}_5}\;{\rm{is}}\;x$, the partial pressure of ${\rm{PC}}{{\rm{l}}_3}$ will be

$\left( {\frac{{2x}}{{1 - x}}} \right)p$

$\left( {\frac{x}{{1 - x}}} \right)p$

NEET UG CHEMISTRY MCQ: Equilibrium

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Phosphorus pentachloride dissociates as follows, in a closed reaction vessel,,br>

\mathrm{PC}{\mathrm{l}_5}\left( \mathrm{g} \right)\leftrightharpoons\mathrm{PC}{\mathrm{l}_3}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right)

If total pressure at equilibrium of the reaction mixture is

p

and degree of dissociation of

\mathrm{PC}{\mathrm{l}_5}\;\mathrm{is}\;x

, the partial pressure of

\mathrm{PC}{\mathrm{l}_3}

will be

View answer and explanation

Correct option: A

\left( {\frac{x}{{x + 1}}} \right)p

Option A (

\left( {\frac{x}{{x + 1}}} \right)p

) is correct because it represents the partial pressure of PCl3 at equilibrium, derived from the degree of dissociation and total pressure.