JEE CHEMISTRY MCQ: HYDROCARBONS

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1 - {\text{Butyne}}\xrightarrow[\begin{subarray}{l} {\text{catalyst}} \\ {\text{controlled}} \\ {\text{readuction}} \end{subarray} ]{{{\text{Lindlar's}}}}A\xrightarrow[\begin{subarray}{l} {\text{Benzoyl}} \\ {\text{peroxide}} \end{subarray} ]{{HCl\,\,{\text{in}}}}B\xrightarrow[{KOH}]{{{\text{alc}}}}C,\,\,\,C

In the above reaction

View answer and explanation

Correct option: B

2-butene

The correct answer is 2-butene because the reaction sequence involves Lindlar's catalyst for reduction to cis-alkene, followed by HCl addition and then elimination.

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