JEE PHYSICS MCQ: RAY OPTICS

1 Medium

1 of 1

Application +4 | -1

A thin sheet of glass

(\mu=1.5)

of thickness 6 microns introduced in the path of one of interfering beams in a double slit experiment shifts the central fringe to a position previously occupied by fifth dark fringe. Then the wavelength of light used is:

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Correct option: A

6600 \mathop {\text{A}}\limits^ \circ

Option A (

6600 \mathop{\text{A}}\limits^\circ

) is correct because it is calculated using the formula for fringe shift due to a thin film.

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