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JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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Spin angular momentum of electron is given by

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Correct option: A

\frac{{\sqrt 3 }}{4}\frac{h}{\pi }

Option A (

\frac{{\sqrt 3 }}{4}\frac{h}{\pi }

) is correct because the spin angular momentum is calculated using the formula

\frac{h}{{2\pi }}\sqrt {s(s + 1)}

, where s = 1/2 for an electron.

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