JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

1 Easy

1 of 1

Application +4 | -1

The sum to

n

terms of the series

\left( {{n^2} - {1^2}} \right) + 2\left( {{n^2} - {2^2}} \right) + 3\left( {{n^2} - {3^2}} \right) + \ldots ,

View answer and explanation

Correct option: A

\frac{{{n^2}}}{4}\left( {{n^2} - 1} \right)

Option A (

\frac{{{n^2}}}{4}\left( {{n^2} - 1} \right)

) is correct because it is derived by expressing the sum as a difference of two summations and using standard summation formulas.

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