Skip to main content
Back to DEFINITE INTEGRATION

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy
1 of 1
Application +4 | -1
Given f′(x)=f′(2−x)f^{\prime}(x)=f^{\prime}(2-x) for all x∈[0,2]x \in[0,2] and f(0)=1,f(2)=e2f(0)=1, f(2)=e^2. Then, ∫02f(x)dx\int_0^2 f(x) d x is equal to
View answer and explanation
Correct option: D
e2+1e^2+1
The correct answer is D (e2+1e^2+1) because after using integration by parts and the given condition f′(x)=f′(2−x)f'(x)=f'(2-x), the integral evaluates to e2+1e^2+1.

More Questions from DEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.