JEE PHYSICS MCQ: SYSTEM OF PARTICLES

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A circular disc '

X

' of radius '

R

' made from iron plate of thickness '

t

' has moment of inertia '

I_x

' about an axis passing through the centre of disc and perpendicular to its plane. Another disc '

Y

' of radius '

3 R

' made from an iron plate of thickness

\left(\frac{t}{3}\right)

has moment of inertia '

I

', about the axis same as that of disc

X

. The relation between

I_x

and

I_y

View answer and explanation

Correct option: D

{I}_{{y}}=27{I}_{{x}}

Option D (

{I}_{{y}}=27{I}_{{x}}

) is correct because the moment of inertia of disc Y is 27 times that of disc X, calculated using the formula for the moment of inertia of a disc.

More Questions from SYSTEM OF PARTICLES

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\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)