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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Let f(x)f(x) be a function satisfying f′(x)=f(x)f^{\prime}(x)=f(x) with f(0)=1f(0)=1 and gg be the function satisfying f(x)+g(x)=x2f(x)+g(x)=x^2.

The value of the integral ∫01f(x)g(x)dx\int_0^1 f(x) g(x) d x is
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Correct option: D
e−12e2−32e-\frac{1}{2} e^2-\frac{3}{2}
Option D is correct because by finding f(x) and g(x), we can evaluate the integral ∫01f(x)g(x)dx\int_0^1 f(x) g(x) d x which results in e−12e2−32e-\frac{1}{2} e^2-\frac{3}{2}.

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