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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
Let Sn=∑r=1nr!S_n=\sum\limits_{{r=1}}^n r!. If Tn=Sn−7[Sn7]T_n=S_n-7\left[\frac{S_n}{7}\right], where [x][x] denotes greatest integer ≤x\leq x, then T100T_{100} is equal to
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Correct option: B
5
The correct answer is 5 because for n >= 6, n! is divisible by 7, so the sum modulo 7 stabilizes, and we can calculate the sum of the first few terms modulo 7.

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