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NEET UG PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A stone dropped from a building of height h and it reaches after t seconds on earth. From the same building if two stones are thrown (one upwards and other downwards) with the same velocity u and they reach the earth surface after t1{t_1} and t2{t_2} seconds respectively, then
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Correct option: C
t=t1t2t = \sqrt {{t_1}{t_2}}
Option C (t=t1t2t = \sqrt {{t_1}{t_2}}) is correct. By analyzing the equations of motion for each scenario and eliminating the initial velocity, we find that the time for the dropped stone is the geometric mean of the times for the stones thrown upwards and downwards.

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