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NEET UG CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Number of electrons in 3dd-orbital of V2+,  Cr2+,  Mn2+{\mathrm{V}^{2 + }},\mathrm{\;C}{\mathrm{r}^{2 + }},\mathrm{\;M}{\mathrm{n}^{2 + }}, and Fe2+\mathrm{F}{\mathrm{e}^{2 + }} are 3, 4, 5 and 6 respectively. Which of the following ions will have largest value of magnetic moment (μ)\left( \mathrm{\mu } \right)?
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Correct option: C
Mn2+\mathrm{M}{\mathrm{n}^{2 + }}
Option C is correct because Mn2+ has 5 unpaired electrons in its 3d orbitals, resulting in the largest magnetic moment according to the formula μ = √n(n+2) BM, where n is the number of unpaired electrons.

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