The electronic configuration of metal $\mathrm{M}$ is $1 \mathrm{s}^2 2 \mathrm{s}^2 2 \mathrm{p}^6 3 \mathrm{s}^1$. The formula of its oxide will be

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NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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The electronic configuration of metal

\mathrm{M}

1 \mathrm{s}^2 2 \mathrm{s}^2 2 \mathrm{p}^6 3 \mathrm{s}^1

. The formula of its oxide will be

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Correct option: B

\mathrm{M}_2 \mathrm{O}

Option B (

\mathrm{M}_2 \mathrm{O}

) is correct because the electronic configuration indicates M has 1 valence electron, so it will form a +1 ion. Oxygen forms a -2 ion, so the formula will be M2O.

NEET UG CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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