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JEE PHYSICS MCQ: WAVES

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The stationary wave y=2a  sin⁡   k  x  cos⁡   ωty = 2a\,\,\sin \,\,\,k\,\,x\,\,\cos \,\,\,\omega t in a closed organ pipe is the result of the superposition of y=a    sin⁡(ωt−kx)y = a\,\,\,\,\sin \left( {\omega t - kx} \right) and
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Correct option: B
y=−a   sin⁡(ωt+kx)y = - a\,\,\,\sin \left( {\omega t + kx} \right)
Option B (y=−a,,sin⁡(ωt+kx)y = - a\\,\\,\sin ( {\omega t + kx} )) is correct because the superposition of the two waves results in the given stationary wave equation.

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