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JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Application +4 | -1

The sum

1\left( {1!} \right) + 2\left( {2\;!} \right) + 3\left( {3!} \right) + ... + n\left( {n!} \right)

equal to

View answer and explanation

Correct option: C

\left( {n + 1} \right)! - 1!

Option C (

\left( {n + 1} \right)! - 1!

) is correct because the sum can be rewritten as a telescoping series, which simplifies to the given expression.

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