Ionization potential of ${\rm{Na}}$ would be numerically the same as:

Electron affinity of ${\rm{N}}{{\rm{a}}^ + }$

Electronegativity of ${\rm{N}}{{\rm{a}}^ + }$

Electron affinity of ${\rm{He}}$

Ionization potential of ${\rm{Mg}}$

Back to CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

1 Medium

1 of 1

Understanding +4 | -1

Ionization potential of

\mathrm{Na}

would be numerically the same as:

View answer and explanation

Correct option: A

Electron affinity of

\mathrm{N}{\mathrm{a}^ + }

Option A is correct because the electron affinity of Na+ is the energy released when an electron is added, which is numerically equal to the ionization energy of Na.

JEE CHEMISTRY MCQ: CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES

More Questions from CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES