The oxidation number of N in ${{\rm{N}}_2}{\rm{H}}_5^ + $ is :

JEE CHEMISTRY MCQ: REDOX REACTIONS

1 Easy

1 of 1

Application +4 | -1

The oxidation number of N in

{\mathrm{N}_2}\mathrm{H}_5^ +

is :

View answer and explanation

Correct option: A

- 2

Option A (-2) is correct because it accurately calculates the oxidation number of N in N2H5+.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.