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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Application +4 | -1
If a1,a2,a3,…,an{a_1},{a_2},{a_3}, \ldots ,{a_n} be an AP of non-zero terms, then 1a1a2+1a2a3+...+1an−1an\frac{1}{{{a_1}{a_2}}} + \frac{1}{{{a_2}{a_3}}} + ... + \frac{1}{{{a_{n - 1}}{a_n}}} is equal to
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Correct option: A
n−1a1an\frac{{n - 1}}{{{a_1}{a_n}}}
Option A, n−1a1an\frac{{n - 1}}{{{a_1}{a_n}}}, is correct because it represents the sum of the series of reciprocals of products of consecutive terms in an arithmetic progression.

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